Glucose when reduced with HI and Red Phosphorus gives

Question

Glucose when reduced with HI and Red Phosphorus gives (A) n-hexane (B) n-heptane (C) n-pentane (D) n-octane

Tardigrade Admin · Accepted Answer

Glucose on complete reduction with Hl and red P finally gives n -hexane. This indicates that it contains a straight chain of six carbon atoms. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/0d6417cd19988313fddf05d23c0a79ce-.png" />

Q. Glucose when reduced with $H I$ and Red Phosphorus gives

$n$ -hexane

$n$ -heptane

$n$ -pentane

$n$ -octane

Glucose on complete reduction with $H l$ and red $P$ finally gives $n$ -hexane. This indicates that it contains a straight chain of six carbon atoms.

Q. Glucose when reduced with HI and Red Phosphorus gives

n-hexane

n-heptane

n-pentane

n-octane