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Chemistry
Glucose when reduced with HI and Red Phosphorus gives
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Q. Glucose when reduced with $HI$ and Red Phosphorus gives
KCET
KCET 2013
Biomolecules
A
$n$-hexane
78%
B
$n$-heptane
8%
C
$n$-pentane
12%
D
$n$-octane
3%
Solution:
Glucose on complete reduction with $Hl$ and red $P$ finally gives $n$ -hexane. This indicates that it contains a straight chain of six carbon atoms.