Given: The compound(s), which on reaction with HNO 3 will give the product having degree of rotation, [α]D=-52.7° is(are)

Question

Given: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/478497469df2fc35d63b1bcea01a7388-.png" /> The compound(s), which on reaction with HNO 3 will give the product having degree of rotation, [α]D=-52.7° is(are) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since, we have to get the product (x) of (α)0=-52.70, i.e. the enantiomer of above product. Which is only possible from (C) (D).

Q. Given:

The compound(s), which on reaction with $H N O_{3}$ will give the product having degree of rotation, $[α]_{D} = - 52. 7^{\circ}$ is(are)

Since, we have to get the product $(x)$ of $(α)_{0} = - 52. 7^{0}$ , i.e. the enantiomer of above product. Which is only possible from (C) $&$ (D).

Q. Given: The compound(s), which on reaction with HNO3​ will give the product having degree of rotation, [α]D​=−52.7∘ is(are)

Since, we have to get the product (x) of (α)0​=−52.70, i.e. the enantiomer of above product. Which is only possible from (C) & (D).

Q. Given:

The compound(s), which on reaction with $H N O_{3}$ will give the product having degree of rotation, $[α]_{D} = - 52. 7^{\circ}$ is(are)

Since, we have to get the product $(x)$ of $(α)_{0} = - 52. 7^{0}$ , i.e. the enantiomer of above product. Which is only possible from (C) $&$ (D).