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Q. Given:
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The compound(s), which on reaction with $HNO _{3}$ will give the product having degree of rotation, $[\alpha]_{D}=-52.7^{\circ}$ is(are)

JEE AdvancedJEE Advanced 2021

Solution:

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Since, we have to get the product $(x)$ of $(\alpha)_{0}=-52.7^{0}$, i.e. the enantiomer of above product. Which is only possible from (C) $\&$ (D).
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