Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5 %, 90 % and 5 %, respectively, the atomic mass of Fe is

Question

Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5 %, 90 % and 5 %, respectively, the atomic mass of Fe is (A) 55.85 (B) 55.95 (C) 55.75 (D) 56.05

Tardigrade Admin · Accepted Answer

Average atomic mass of Fe =((54×5)+(56×90)+(57×5)/100)=55.95

Q. Given that the abundances of isotopes $^{54} F e,^{56} F e$ and $^{57} F e$ are $5%, 90%$ and $5%$ , respectively, the atomic mass of Fe is

$55.85$

$55.95$

$55.75$

$56.05$

Average atomic mass of $F e$
$= \frac{( 54 \times 5 ) + ( 56 \times 90 ) + ( 57 \times 5 )}{100} = 55.95$

Q. Given that the abundances of isotopes 54Fe,56Fe and 57Fe are 5%,90% and 5%, respectively, the atomic mass of Fe is

55.85

55.95

55.75

56.05