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Chemistry
Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5 %, 90 % and 5 %, respectively, the atomic mass of Fe is
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Q. Given that the abundances of isotopes $^{54}Fe, ^{56}Fe$ and $^{57}Fe$ are $5\%, 90\%$ and $5\%$, respectively, the atomic mass of Fe is
Structure of Atom
A
$55.85$
100%
B
$55.95$
0%
C
$55.75$
0%
D
$56.05$
0%
Solution:
Average atomic mass of $Fe$
$=\frac{\left(54\times5\right)+\left(56\times90\right)+\left(57\times5\right)}{100}=55.95$