Given that T stands for time period and I stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation T2=l/g is correct?

Question

Given that T stands for time period and I stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation T2=l/g is correct? (A) It is correct both dimensionally as well as numerically (B) It is neither dimensionally correct nor numerically (C) It is dimensionally correct but not numerically (D) It is numerically correct but not dimensionally

Tardigrade Admin · Accepted Answer

The correct relation for time period of simple pendulum is T=2π (l/g)1/2 . So, the given relation is numerically incorrect as the factor of 2π is missing. But it is correct dimensionally.

Q. Given that $T$ stands for time period and $I$ stands for the length of simple pendulum. If $g$ is the acceleration due to gravity, then which of the following statements about the relation $T^{2} = l / g$ is correct?

It is correct both dimensionally as well as numerically

It is neither dimensionally correct nor numerically

It is dimensionally correct but not numerically

It is numerically correct but not dimensionally

The correct relation for time period of simple pendulum is
$T = 2 π (l / g)^{1/2}$ .
So, the given relation is numerically incorrect as the factor of $2 π$ is missing. But it is correct dimensionally.

Q. Given that T stands for time period and I stands for the length of simple pendulum. If g is the acceleration due to gravity, then which of the following statements about the relation T2=l/g is correct?