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Q. Given that $T$ stands for time period and $I$ stands for the length of simple pendulum. If $g$ is the acceleration due to gravity, then which of the following statements about the relation $ {{T}^{2}}=l/g $ is correct?

ManipalManipal 2008Gravitation

Solution:

The correct relation for time period of simple pendulum is
$ T=2\pi {{(l/g)}^{1/2}} $ .
So, the given relation is numerically incorrect as the factor of $ 2\pi $ is missing. But it is correct dimensionally.