Given that CH4(g) + 360 kJ → C (g) + 4H(g)C2H6(g) +620 kJ → 2C(g) + 6H(g) The value of C-C bond energy is

Question

Given that CH4(g) + 360 kJ → C (g) + 4H(g)C2H6(g) +620 kJ → 2C(g) + 6H(g) The value of C-C bond energy is (A) 260 kJ mol-1 (B) 180 kJ mol-1 (C) 130 kJ mol-1 (D) 80 kJ mor-1

Tardigrade Admin · Accepted Answer

From 1st eqn. ΔHC . H = (360/4) = 90 kJ mol-1 From 2nd eqn. 6Δ HC-H + Δ HC-C = 620 kJ Δ HC -C = 620 - 6Δ HC -H = 620 - 6 × 90 = 80 : kJ : mol-1

Q. Given that $C H_{4} (g) + 360 k J \to C (g) + 4 H (g) C_{2} H_{6} (g) + 620 k J \to 2 C (g) + 6 H (g)$ The value of C-C bond energy is

$260 k J m o l^{- 1}$

$180 k J m o l^{- 1}$

$130 k J m o l^{- 1}$

$80 k J m o r^{- 1}$

From 1st eqn. $Δ$ HC . H = $\frac{360}{4}$ = 90 kJ $m o l^{- 1}$
From 2nd eqn. 6 $Δ H_{C - H} + Δ H_{C - C}$ = 620 kJ
$Δ H_{C - C} = 620 - 6Δ H_{C - H}$
$= 620 - 6 \times 90 = 80 k J m o l^{- 1}$

Q. Given that CH4​(g)+360kJ→C(g)+4H(g)C2​H6​(g)+620kJ→2C(g)+6H(g) The value of C-C bond energy is

260kJmol−1

180kJmol−1

130kJmol−1

80kJmor−1