1. Tardigrade
  2. Question
  3. Chemistry
  4. Given that CH4(g) + 360 kJ → C (g) + 4H(g)C2H6(g) +620 kJ → 2C(g) + 6H(g) The value of C-C bond energy is

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Q. Given that $CH_4(g) + 360 kJ \to C (g) + 4H(g)C_2H_6(g) +620 kJ \to 2C(g) + 6H(g)$ The value of C-C bond energy is

Thermodynamics

Solution:

From 1st eqn. $\Delta$HC . H = $\frac{360}{4}$ = 90 kJ $mol^{-1}$
From 2nd eqn. 6$\Delta H_{C-H} + \Delta H_{C-C}$ = 620 kJ
$\Delta H_{C -C} = 620 - 6\Delta H_{C -H} $
$= 620 - 6 \times 90 = 80 \: kJ \: mol^{-1}$