Given :- Fe3 + (aq) + 3e- → Fe2+ (aq); E°= + 0.77 V Al3 + (aq) +3e- → Al(s); E°= -1.66 V Br2(aq) + 2e--2Br- ; E°= + 1.09 V Considering the electrode potentials. which of the following represents the correct order of reducing power ?

Question

Given :- Fe3 + (aq) + 3e- → Fe2+ (aq); E°= + 0.77 V Al3 + (aq) +3e- → Al(s); E°= -1.66 V Br2(aq) + 2e-->2Br- ; E°= + 1.09 V Considering the electrode potentials. which of the following represents the correct order of reducing power ? (A) Fe2 + < Al < Br- (B) Br- < Fe2+ < Al (C) Al < Br- < Fe2+ (D) Al < Fe2+ < Br-

Tardigrade Admin · Accepted Answer

A negative E ° means that the redox couple is a stronger reducing agent. Hence, we can say that Aluminium is strongest reducing agent.

$F e^{2} + < A l < B r^{-}$

$B r^{-} < F e^{2 +} < A l$

$A l < B r^{-} < F e 2 +$

$A l < F e^{2 +} < B r^{-}$

A negative $E^{\circ}$ means that the redox couple is a stronger reducing agent. Hence, we can say that Aluminium is strongest reducing agent.

Q. Given :- Fe3​+(aq)+3e−→Fe2+(aq);E∘=+0.77V Al3+(aq)+3e−→Al(s);E∘=−1.66V Br2​(aq)+2e−−>2Br−;E∘=+1.09V Considering the electrode potentials. which of the following represents the correct order of reducing power ?

Fe2+<Al<Br−

Br−<Fe2+<Al

Al<Br−<Fe2+

Al<Fe2+<Br−

A negative E∘ means that the redox couple is a stronger reducing agent. Hence, we can say that Aluminium is strongest reducing agent.

$F e^{2} + < A l < B r^{-}$

$B r^{-} < F e^{2 +} < A l$

$A l < B r^{-} < F e 2 +$

$A l < F e^{2 +} < B r^{-}$

A negative $E^{\circ}$ means that the redox couple is a stronger reducing agent. Hence, we can say that Aluminium is strongest reducing agent.