1. Tardigrade
  2. Question
  3. Chemistry
  4. Given :- Fe3 + (aq) + 3e- → Fe2+ (aq); E°= + 0.77 V Al3 + (aq) +3e- → Al(s); E°= -1.66 V Br2(aq) + 2e-->2Br- ; E°= + 1.09 V Considering the electrode potentials. which of the following represents the correct order of reducing power ?

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Q. Given :-
$Fe_{3} + \left(aq\right) + 3e^{-} \to Fe^{2}+ \left(aq\right); E^{\circ}= + 0.77 \,V$
$Al^{3} + \left(aq\right) +3e^{-} \to Al\left(s\right); E^{\circ}= -1.66\, V$
$Br_{2}\left(aq\right) + 2e^{-}->2Br^{-} ; E^{\circ}= + 1.09 \,V$
Considering the electrode potentials. which of the following represents the correct order of reducing power ?

JEE MainJEE Main 2014Electrochemistry

Solution:

A negative $E ^{\circ}$ means that the redox couple is a stronger reducing agent. Hence, we can say that Aluminium is strongest reducing agent.