Given, E° Cr 3+/Cr =-0.74 V;E°MnO-4/Mn2+=1.51 V E° Cr2 O 2-7/Cr3+ =-1.33 V;E°Cl/Cl-=1.36 V Based on the data given above strongest oxidising agent will be

Question

Given, E° Cr 3+/Cr =-0.74 V;E°MnO-4/Mn2+=1.51 V E° Cr2 O 2-7/Cr3+ =-1.33 V;E°Cl/Cl-=1.36 V Based on the data given above strongest oxidising agent will be (A) Cl (B) Cr3+ (C) Mn2+ (D) MnO-4

Tardigrade Admin · Accepted Answer

Higher the standard reduction potential, better is oxidising agent. Among the given E°MnO-4/Mn2+ is highest MnO-4 is the strongest oxidising agent.

Q. Given, $E_{C r^{3 +} / C r}^{\circ} = - 0.74 V; E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V$
$E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{\circ} = - 1.33 V; E_{Cl / C l^{-}}^{\circ} = 1.36 V$
Based on the data given above strongest oxidising agent will be

$Cl$

$C r^{3 +}$

$M n^{2 +}$

$M n O_{4}^{-}$

Higher the standard reduction potential, better is oxidising agent. Among the given $E_{M n O_{4}^{-} / M n^{2 +}}^{\circ}$ is highest $M n O_{4}^{-}$ is the strongest oxidising agent.

Q. Given, ECr3+/Cr∘​=−0.74V;EMnO4−​/Mn2+∘​=1.51V ECr2​O72−​/Cr3+∘​=−1.33V;ECl/Cl−∘​=1.36V Based on the data given above strongest oxidising agent will be

Cl

Cr3+

Mn2+

MnO4−​