1. Tardigrade
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  3. Chemistry
  4. Given, E° Cr 3+/Cr =-0.74 V;E°MnO-4/Mn2+=1.51 V E° Cr2 O 2-7/Cr3+ =-1.33 V;E°Cl/Cl-=1.36 V Based on the data given above strongest oxidising agent will be

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Q. Given, $E^\circ _{Cr ^{3+}/Cr} =-0.74\, V;E^\circ_{MnO^-_4/Mn^{2+}}=1.51\, V$
$\, \, \, \, \, E^\circ _{Cr_2 O ^{2-}_7/Cr^{3+}} =-1.33\, V;E^\circ_{Cl/Cl^-}=1.36\, V$
Based on the data given above strongest oxidising agent will be

JEE MainJEE Main 2013Redox Reactions

Solution:

Higher the standard reduction potential, better is oxidising agent. Among the given $E^\circ_{MnO^-_4/Mn^{2+}}$ is highest $MnO^-_4$ is the strongest oxidising agent.