Given below are the statements about diborane (a) Diborane is prepared by the oxidation of NaBH 4 with I2 (b) Each boron atom is in sp 2 hybridized state (c) Diborane has one bridged 3 centre-2-electron bond (d) Diborane is a planar molecule The option with correct statement(s) is -

Question

Given below are the statements about diborane (a) Diborane is prepared by the oxidation of NaBH 4 with I2 (b) Each boron atom is in sp 2 hybridized state (c) Diborane has one bridged 3 centre-2-electron bond (d) Diborane is a planar molecule The option with correct statement(s) is - (A) (c) and (d) only (B) (a) only (C) (c) only (D) (a) and (b) only

Tardigrade Admin · Accepted Answer

Diborane is prepared by the reaction of NaBH 4 with I2. 2 NaBH 4+ I 2 arrow B 2 H 6+2 NaI + H 2 In diborane, 'B' is sp 3 hybrid, it is Non-planar and two 3 c-2 e-bonds are present.

Q. Given below are the statements about diborane (a) Diborane is prepared by the oxidation of NaBH4​ with I2​ (b) Each boron atom is in sp 2 hybridized state (c) Diborane has one bridged 3 centre-2-electron bond (d) Diborane is a planar molecule The option with correct statement(s) is -

(c) and (d) only

(a) only

(c) only

(a) and (b) only

Diborane is prepared by the reaction of NaBH4​ with I2​. 2NaBH4​+I2​→B2​H6​+2NaI+H2​ In diborane, 'B' is sp3 hybrid, it is Non-planar and two 3c−2e−bonds are present.

Diborane is prepared by the reaction of $N a B H_{4}$ with $I_{2}$ .
$2 N a B H_{4} + I_{2} \to B_{2} H_{6} + 2 N a I + H_{2}$
In diborane, ' $B$ ' is $s p^{3}$ hybrid, it is Non-planar and two $3 c - 2 e^{-}$ bonds are present.