Question

Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of $NaBH _{4}$ with $I_{2}$
(b) Each boron atom is in sp ${ }^{2}$ hybridized state
(c) Diborane has one bridged $3$ centre-$2$-electron bond
(d) Diborane is a planar molecule
The option with correct statement(s) is -

• A. (c) and (d) only
• B. (a) only
• C. (c) only
• D. (a) and (b) only

Answer 1

Answer: (B)

Diborane is prepared by the reaction of $NaBH _{4}$ with $I_{2}$.
$2 NaBH _{4}+ I _{2} \rightarrow B _{2} H _{6}+2 NaI + H _{2}$
In diborane, '$B$' is $sp { }^{3}$ hybrid, it is Non-planar and two $3 c-2 e^{-}$bonds are present.