Q.
Given below are the diameters of circles (in mm) drawn in a design.
Diameter
33 - 36
37 - 40
41 - 44
45 -48
49 - 52
Number of circles
15
17
21
22
25
find the mean diameter of the circles.
Diameter | 33 - 36 | 37 - 40 | 41 - 44 | 45 -48 | 49 - 52 |
Number of circles | 15 | 17 | 21 | 22 | 25 |
Solution:
Converting the given series into an exclusive series we prepare the table given below.
Class
Frequency
Mid point
32.5 - 36.5
15
34.5
-2
4
-30
60
36.5 - 40.5
17
38.5
-1
1
-17
17
40.5 - 44.5
21
42.5=A
0
0
0
0
44.5 - 48.5
22
46.5
1
1
22
22
48.5 - 52.5
25
50.5
2
4
50
100
N=100
25
199
,
and .
Thus the mean
Class | Frequency | Mid point | ||||
---|---|---|---|---|---|---|
32.5 - 36.5 | 15 | 34.5 | -2 | 4 | -30 | 60 |
36.5 - 40.5 | 17 | 38.5 | -1 | 1 | -17 | 17 |
40.5 - 44.5 | 21 | 42.5=A | 0 | 0 | 0 | 0 |
44.5 - 48.5 | 22 | 46.5 | 1 | 1 | 22 | 22 |
48.5 - 52.5 | 25 | 50.5 | 2 | 4 | 50 | 100 |
N=100 | 25 | 199 |