Given at 350 K pA°=300 torr and pB°=800 torr the composition of the mixture having a normal boiling point of 350 K is:

Question

Given at 350 K pA°=300 torr and pB°=800 torr the composition of the mixture having a normal boiling point of 350 K is: (A) XA=0.08 (B) XA=0.06 (C) XA=0.04 (D) XA=0.02

Tardigrade Admin · Accepted Answer

760=300 XA+800(1-XA) ⇒ 760=800-500 XA ⇒ 500 XA=40 ∴ XA=(40/500)=0.08

Q. Given at $350 K p_{A}^{\circ} = 300$ torr and $p_{B}^{\circ} = 800$ torr the composition of the mixture having a normal boiling point of 350 K is:

$X_{A} = 0.08$

$X_{A} = 0.06$

$X_{A} = 0.04$

$X_{A} = 0.02$

$760 = 300 X_{A} + 800 (1 - X_{A})$
$\Rightarrow 760 = 800 - 500 X_{A}$
$\Rightarrow 500 X_{A} = 40$
$∴ X_{A} = \frac{40}{500} = 0.08$

Q. Given at 350KpA∘​=300 torr and pB∘​=800 torr the composition of the mixture having a normal boiling point of 350 K is:

XA​=0.08

XA​=0.06

XA​=0.04

XA​=0.02