1. Tardigrade
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  3. Chemistry
  4. Given at 350 K pA°=300 torr and pB°=800 torr the composition of the mixture having a normal boiling point of 350 K is:

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Q. Given at $350\,K p_{A}^{\circ}=300$ torr and $p_{B}^{\circ}=800$ torr the composition of the mixture having a normal boiling point of 350 K is:

Solutions

Solution:

$760=300\,X_{A}+800(1-X_{A})$
$\Rightarrow 760=800-500\,X_{A}$
$\Rightarrow 500\,X_{A}=40$
$\therefore X_{A}=\frac{40}{500}=0.08$