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Tardigrade
Question
Chemistry
Give: E0Mn+7|Mn+2 = 1.5 V and E0Mn+4|Mn+2 = 1.2 V, then E0Mn+7|Mn+4 is
Q. Give: E
0
Mn
+7
|Mn
+2
= 1.5 V and E
0
Mn
+4
|Mn
+2
= 1.2 V, then E
0
Mn
+7
|Mn
+4
is
4032
147
KCET
KCET 2019
Electrochemistry
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A
1.7 V
32%
B
2.1 V
17%
C
0.3 V
44%
D
0.1 V
7%
Solution:
M
n
+
7
+
5
e
−
→
M
n
2
+
M
n
+
4
+
2
e
−
→
M
n
2
+
R
e
q
u
i
re
d
e
q
u
a
t
i
o
n
M
n
+
7
+
3
e
−
→
M
n
4
+
∴
−
3
F
E
º
−
=
−
7.5
F
+
2.4
F
∴
E
º
−
=
1.7
V
Δ
G
º
−
=
−
5
F
1.5
,
Δ
G
º
−
=
−
2
F
1.2
,
Δ
G
º
−
=
−
3
F
E
º
−