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Q. Give: E0Mn+7|Mn+2 = 1.5 V and E0Mn+4|Mn+2 = 1.2 V, then E0Mn+7|Mn+4 is

KCETKCET 2019Electrochemistry

Solution:

$Mn^{+7} +5e^{-} \to Mn^{2+}$
$Mn^{+4}+2e^{-} \to Mn^{2+}$
$Required \, equation$
$Mn^{+7}+3e^{-} \to Mn^{4+}$
$\therefore \, -3FE^{º-}=-7.5F+2.4F$
$\therefore \, E^{º-}=1.7 V$
$\Delta G^{º-}=-5 F 1.5,$
$\Delta G^{º-}=-2 F 1.2, $
$\Delta G^{º-}=-3FE^{º-}$