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Tardigrade
Question
Mathematics
Geometric mean of tan 1°, tan 2°, ldots ldots . ldots, tan 89° is
Q. Geometric mean of
tan
1
∘
,
tan
2
∘
,
……
.
…
,
tan
8
9
∘
is
1991
228
AP EAMCET
AP EAMCET 2020
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A
89
1
B
1
C
3
1
D
3
Solution:
tan
1
∘
⋅
tan
2
∘
…
tan
4
5
∘
⋅
tan
4
6
∘
…
tan
8
8
∘
⋅
tan
8
9
∘
tan
1
∘
⋅
tan
2
∘
…
tan
4
4
∘
⋅
tan
4
5
∘
tan
(
90
−
4
4
∘
)
…
tan
(
9
0
∘
−
1
∘
)
tan
1
∘
⋅
tan
2
∘
…
tan
4
4
∘
tan
4
5
∘
Cot
4
4
∘
⋅
Cot
4
3
∘
…
Cot
1
∘
tan
1
∘
⋅
tan
2
∘
…
tan
4
4
∘
1
t
a
n
4
4
∘
1
t
a
n
4
3
∘
1
⋯
s
t
a
n
1
∘
1
=
1