General configuration of outermost and penultimate shell is(n-1)s2(n-1)p6 (n-1)d1ns2. If n = 4 and x = 5 then no. of protons in the nucleus will be

Question

General configuration of outermost and penultimate shell is(n-1)s2(n-1)p6 (n-1)d1ns2. If n = 4 and x = 5 then no. of protons in the nucleus will be (A) >25 (B) < 24 (C) 25 (D) 30

Tardigrade Admin · Accepted Answer

Substituting the values, we get the configuration to be

[N e] 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5}

.
The atomic number is

10 + 2 + 6 + 2 + 5 = 25

.
Number of proton

=

Atomic number
Therefore, the number of protons in the nucleus is 25 .

Q. General configuration of outermost and penultimate shell is $(n - 1) s^{2} (n - 1) p^{6} (n - 1) d^{1} n s^{2}$ . If $n = 4$ and $x = 5$ then no. of protons in the nucleus will be

$> 25$

$< 24$

$25$

$30$

Substituting the values, we get the configuration to be $[N e] 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5}$ .
The atomic number is $10 + 2 + 6 + 2 + 5 = 25$ .
Number of proton $=$ Atomic number
Therefore, the number of protons in the nucleus is 25 .

Q. General configuration of outermost and penultimate shell is(n−1)s2(n−1)p6(n−1)d1ns2. If n=4 and x=5 then no. of protons in the nucleus will be

>25

<24

25

30