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  3. Chemistry
  4. General configuration of outermost and penultimate shell is(n-1)s2(n-1)p6 (n-1)d1ns2. If n = 4 and x = 5 then no. of protons in the nucleus will be

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Q. General configuration of outermost and penultimate shell is$\left(n-1\right)s^{2}\left(n-1\right)p^{6} \left(n-1\right)d^{1}ns^{2}$. If $n = 4$ and $x = 5$ then no. of protons in the nucleus will be

The d-and f-Block Elements

Solution:

Substituting the values, we get the configuration to be $[ Ne ] 3 s ^{2} 3 p ^{6} 4 s ^{2} 3 d ^{5}$.
The atomic number is $10+2+6+2+5=25$.
Number of proton $=$ Atomic number
Therefore, the number of protons in the nucleus is 25 .