From the following E ° values of half-cells; i. A + e longrightarrow A - ; E °=-0.24 V ii. B -+ e longrightarrow B 2- ; E °=+1.25 V iii. C -+2 e longrightarrow C 3- ; E °=-1.25 V iv. D +2 e longrightarrow D 2- ; E °=+0.68 V If you were to construct a cell using combination of two half-cells from above that gives the largest cell potential, then value of the largest cell potential would be V

Question

From the following E ° values of half-cells; i. A + e longrightarrow A - ; E °=-0.24 V ii. B -+ e longrightarrow B 2- ; E °=+1.25 V iii. C -+2 e longrightarrow C 3- ; E °=-1.25 V iv. D +2 e longrightarrow D 2- ; E °=+0.68 V If you were to construct a cell using combination of two half-cells from above that gives the largest cell potential, then value of the largest cell potential would be V (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Larger the difference between the electrode potentials, greater is the cell potential. Hence, combination of half-cells

(ii)

and

(iii)

will give the largest cell potential.

E_{cell}^{\circ} = E_{cathode}^{\circ} - E_{anode}^{\circ} = 1.25 - (- 1.25)

= + 2.50 V

Larger the difference between the electrode potentials, greater is the cell potential. Hence, combination of half-cells (ii) and (iii) will give the largest cell potential. Ecell ∘​=Ecathode ∘​−Eanode ∘​=1.25−(−1.25) =+2.50V

Larger the difference between the electrode potentials, greater is the cell potential. Hence, combination of half-cells $(ii)$ and $(iii)$ will give the largest cell potential.
$E_{cell}^{\circ} = E_{cathode}^{\circ} - E_{anode}^{\circ} = 1.25 - (- 1.25)$
$= + 2.50 V$