1. Tardigrade
  2. Question
  3. Chemistry
  4. From the following E ° values of half-cells; i. A + e longrightarrow A - ; E °=-0.24 V ii. B -+ e longrightarrow B 2- ; E °=+1.25 V iii. C -+2 e longrightarrow C 3- ; E °=-1.25 V iv. D +2 e longrightarrow D 2- ; E °=+0.68 V If you were to construct a cell using combination of two half-cells from above that gives the largest cell potential, then value of the largest cell potential would be V

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Q. From the following $E ^{\circ}$ values of half-cells;
i. $A + e \longrightarrow A ^{-} ; E ^{\circ}=-0.24\, V$
ii. $B ^{-}+ e \longrightarrow B ^{2-} ; E ^{\circ}=+1.25\, V$
iii. $C ^{-}+2 e \longrightarrow C ^{3-} ; E ^{\circ}=-1.25\, V$
iv. $D +2 e \longrightarrow D ^{2-} ; E ^{\circ}=+0.68\, V$
If you were to construct a cell using combination of two half-cells from above that gives the largest cell potential, then value of the largest cell potential would be______ $V$

Electrochemistry

Solution:

Larger the difference between the electrode potentials, greater is the cell potential. Hence, combination of half-cells $(ii)$ and $(iii)$ will give the largest cell potential.
$E _{\text {cell }}^{\circ}= E _{\text {cathode }}^{\circ}- E _{\text {anode }}^{\circ} =1.25-(-1.25)$
$=+2.50\, V$