From an automatic gun a man fires 360 bullet per minute with a speed of 360 km/h. If each weighs 20g, the power of the gun is

Question

From an automatic gun a man fires 360 bullet per minute with a speed of 360 km/h. If each weighs 20g, the power of the gun is (A) 600 W (B) 300 W (C) 150 W (D) 75 W

Tardigrade Admin · Accepted Answer

Power of gun =(Total KE of fired bullet/Time) =(n× (1/2)mv2/t)[∵ 360 km/h=100 m/s] =(360/60)× (1/2)× 2× 10-2× (100)2 =600 W

Q. From an automatic gun a man fires 360 bullet per minute with a speed of 360 km/h. If each weighs 20g, the power of the gun is

600 W

300 W

150 W

75 W

Power of gun $= \frac{T o t a l K E o f f i re d b u ll e t}{T im e}$ $= \frac{n \times \frac{1}{2} m v ^{2}}{t} [∵ 360 km / h = 100 m / s]$ $= \frac{360}{60} \times \frac{1}{2} \times 2 \times 10^{- 2} \times (100)^{2}$ $= 600 W$

Q. From an automatic gun a man fires 360 bullet per minute with a speed of 360 km/h. If each weighs 20g, the power of the gun is

600 W

300 W

150 W

75 W

Power of gun =TimeTotalKEoffiredbullet​ =tn×21​mv2​[∵360km/h=100m/s] =60360​×21​×2×10−2×(100)2 =600W

Power of gun $= \frac{T o t a l K E o f f i re d b u ll e t}{T im e}$ $= \frac{n \times \frac{1}{2} m v ^{2}}{t} [∵ 360 km / h = 100 m / s]$ $= \frac{360}{60} \times \frac{1}{2} \times 2 \times 10^{- 2} \times (100)^{2}$ $= 600 W$