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Q. From an automatic gun a man fires 360 bullet per minute with a speed of 360 km/h. If each weighs 20g, the power of the gun is

Rajasthan PMTRajasthan PMT 2010

Solution:

Power of gun $ =\frac{Total\,\,KE\,\,of\,\,fired\,\,bullet}{Time} $ $ =\frac{n\times \frac{1}{2}m{{v}^{2}}}{t}[\because \,\,360\,\,km/h=100\,\,m/s] $ $ =\frac{360}{60}\times \frac{1}{2}\times 2\times {{10}^{-2}}\times {{(100)}^{2}} $ $ =600\,\,W $