From a tower of height 45 m , a stone is dropped, calculate the total distance travelled by the stone during the last one second of motion? (Given: g=10 m/s2 )

Question

From a tower of height 45 m , a stone is dropped, calculate the total distance travelled by the stone during the last one second of motion? (Given: g=10 m/s2 ) (A) 4.5 m (B) 10 m (C) 25 m (D) 35 m

Tardigrade Admin · Accepted Answer

S=ut+(1/2)at2 u=0 t=√(2 S/g)=3s Distance covered in 3rd second (last second) ⇒ D3=u+(a/2)(.2× 3-1.)=25 m

Q. From a tower of height $45 m$ , a stone is dropped, calculate the total distance travelled by the stone during the last one second of motion? (Given: $g = 10 m / s^{2}$ )

$4.5 m$

$10 m$

$25 m$

$35 m$

$S = u t + \frac{1}{2} a t^{2}$
$u = 0$
$t = \frac{2 S}{g} = 3 s$
Distance covered in $3$ rd second (last second)
$\Rightarrow D_{3} = u + \frac{a}{2} (2 \times 3 - 1) = 25 m$

Q. From a tower of height 45m , a stone is dropped, calculate the total distance travelled by the stone during the last one second of motion? (Given: g=10m/s2 )

4.5m

10m

25m

35m