Q.
From a balloon rising vertically upwards as 5m/s a stone is thrown up at 10m/s relative to the balloon. Its velocity with respect to ground after 2s is (assume g=10m/s2 )
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J & K CETJ & K CET 2006Motion in a Straight Line
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Solution:
The initial velocity with respect to ground will be 10+5=15m/s
after 2 sec its velocity will be v=15−gt=15−10×2=−5m/s
Whose value is 5m/s
Once the stone is projected from balloon it will not have any impact of the balloon after that moment.