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Q. From a balloon rising vertically upwards as $ 5\,m/s $ a stone is thrown up at $10 \,m/s$ relative to the balloon. Its velocity with respect to ground after $ 2\,s $ is (assume $ g=10\,m/s^{2} $ )

J & K CETJ & K CET 2006Motion in a Straight Line

Solution:

The initial velocity with respect to ground will be $10+5=15 m / s$ after 2 sec its velocity will be $v =15- gt =15-10 \times 2=-5 m / s$ Whose value is $5 m / s$ Once the stone is projected from balloon it will not have any impact of the balloon after that moment.