Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be

Question

Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be (A)  (2ε 0A/d)  (B)  (ε 0A/d)  (C)  (3ε 0A/d)  (D)  (3ε 0A/2d)

Tardigrade Admin · Accepted Answer

The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence, equivalent capacitance =3C=(3 ε0 A/d)

Q. Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is $d$ . The equivalent capacity between $A$ and $B$ will be

$\frac{2 ε _{0} A}{d}$

$\frac{ε _{0} A}{d}$

$\frac{3 ε _{0} A}{d}$

$\frac{3 ε _{0} A}{2 d}$

The given arrangement is equivalent to the parallel combination of three identical capacitors.
Hence, equivalent capacitance
$= 3 C = \frac{3 ε _{0} A}{d}$

Q. Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be

d2ε0​A​

dε0​A​

d3ε0​A​

2d3ε0​A​