Question

Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is $d$. The equivalent capacity between $A$ and $B$ will be

• A. $ \frac{2{{\varepsilon }_{0}}A}{d} $
• B. $ \frac{{{\varepsilon }_{0}}A}{d} $
• C. $ \frac{3{{\varepsilon }_{0}}A}{d} $
• D. $ \frac{3{{\varepsilon }_{0}}A}{2d} $

Answer 1

Answer: (C)

The given arrangement is equivalent to the parallel combination of three identical capacitors.
Hence, equivalent capacitance
$=3C=\frac{3 \varepsilon_{0} A}{d}$