Q.
Four identical charges each of charge q are placed at the corners of a square. Then at the center of the square.the resultant electric intensity' E and the net electric potential V are
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Electrostatic Potential and Capacitance
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Solution:
→ electic field by the diagonality opposits changes canal each other ∴E=0
voltage:
we know V=eKV (E is vector V is a scalar ) V=a2KV
total V=a42KV ∴E=0,V=0