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Q. Four identical charges each of charge q are placed at the corners of a square. Then at the center of the square.the resultant electric intensity' E and the net electric potential V are

Electrostatic Potential and Capacitance

Solution:

$\rightarrow$ electic field by the diagonality opposits changes canal each other
$\therefore E =0$
voltage:
we know $V=\frac{K V}{e}$
$(E$ is vector $V$ is a scalar $)$
$V =\frac{\sqrt{2} KV }{ a }$
total $V =\frac{4 \sqrt{2} KV }{ a }$
$\therefore E =0, V \neq 0$