Four different sets of quantum numbers for four electrons are given below: e1=4,0,0,-(1/2) ; e2=3,1,1,-(1/2) e3=3,2,2,+(1/2) ; e4=3,0,0,+(1/2) The order of energy of e1, e2, e3 and e4 is

Question

Four different sets of quantum numbers for four electrons are given below: e1=4,0,0,-(1/2) ; e2=3,1,1,-(1/2) e3=3,2,2,+(1/2) ; e4=3,0,0,+(1/2) The order of energy of e1, e2, e3 and e4 is (A) e1>e2>e3>e4 (B) e4>e3>e2>e1 (C) e3>e1>e2>e4 (D) e2>e3>e4>e1

Tardigrade Admin · Accepted Answer

Higher (n+l) value higher is the energy and for same (n+l) value higher n, higher will be the energy. Thus, e3 > e1 > e2 > e4

Q. Four different sets of quantum numbers for four electrons are given below:
$e_{1} = 4, 0, 0, - \frac{1}{2}; e_{2} = 3, 1, 1, - \frac{1}{2}$
$e_{3} = 3, 2, 2, + \frac{1}{2}; e_{4} = 3, 0, 0, + \frac{1}{2}$
The order of energy of $e_{1}, e_{2}, e_{3}$ and $e_{4}$ is

$e_{1} > e_{2} > e_{3} > e_{4}$

$e_{4} > e_{3} > e_{2} > e_{1}$

$e_{3} > e_{1} > e_{2} > e_{4}$

$e_{2} > e_{3} > e_{4} > e_{1}$

Higher $(n + l)$ value higher is the energy and for same $(n + l)$ value higher $n$ , higher will be the energy. Thus, $e_{3} > e_{1} > e_{2} > e_{4}$

Q. Four different sets of quantum numbers for four electrons are given below: e1​=4,0,0,−21​;e2​=3,1,1,−21​ e3​=3,2,2,+21​;e4​=3,0,0,+21​ The order of energy of e1​,e2​,e3​ and e4​ is

e1​>e2​>e3​>e4​

e4​>e3​>e2​>e1​

e3​>e1​>e2​>e4​

e2​>e3​>e4​>e1​