Question

Four different sets of quantum numbers for four electrons are given below:
$e_{1}=4,0,0,-\frac{1}{2} ; e_{2}=3,1,1,-\frac{1}{2}$
$e_{3}=3,2,2,+\frac{1}{2} ; e_{4}=3,0,0,+\frac{1}{2}$
The order of energy of $e_{1}, e_{2}, e_{3}$ and $e_{4}$ is

• A. $e_{1}>e_{2}>e_{3}>e_{4}$
• B. $e_{4}>e_{3}>e_{2}>e_{1}$
• C. $e_{3}>e_{1}>e_{2}>e_{4}$
• D. $e_{2}>e_{3}>e_{4}>e_{1}$

Answer 1

Answer: (C)

Higher $(n+l)$ value higher is the energy and for same $(n+l)$ value higher $n$, higher will be the energy. Thus, $e_{3} > e_{1} > e_{2} > e_{4}$