Question

For the zeroth order reaction, sets I and II are given, hence $x$ is

• A. 2 min
• B. 4 min
• C. 6 min
• D. 8 min

Answer 1

Answer: (C)

By set I, half-life is $2$ min. In set-II, number of moles have been doubled, thus half-life is also doubled, i.e., now it is $4$ min. Thus, $8$ mol change to $4$ mol (half) in $=4$ min and $4$ mol change to $2$ mol (half) in $=2$ min. Thus, total time $=4+2=6$ min.