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  4. For the zeroth order reaction, sets I and II are given, hence x is<img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/chemistry/95d95bf06b0d3ce88643236f5bf5ae4f-.png />

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Q. For the zeroth order reaction, sets I and II are given, hence $ x $ is
image

Bihar CECEBihar CECE 2013

Solution:

By set I, half-life is $2$ min. In set-II, number of moles have been doubled, thus half-life is also doubled, i.e., now it is $4$ min. Thus, $8$ mol change to $4$ mol (half) in $=4$ min and $4$ mol change to $2$ mol (half) in $=2$ min. Thus, total time $=4+2=6$ min.