Question

For the redox reaction

$Mn{O}_4^{-}+C_2{O}_4^{2-}+H^{+}\to M{n}^{2+}+C{O}_2+H_{2}O$

The correct coefficients of the reactants for the balanced equation are

$Mn{O}_4^{-}$ $C_2{O}_4^{2-}$ $H^{+}$

$Mn{O}_4^{-}$	$C_2{O}_4^{2-}$	$H^{+}$
2	16	5
2	5	16
16	5	2
5	16	2

• A. A
• B. B
• C. C
• D. D

Answer 1

Answer: (B)

n-factor of $Mn{O}_4^{-}\Rightarrow 5$

n-factor of $C_2{O}_4^{2-}\Rightarrow 2$

Ratio of n-factors of $Mn{O}_4^{-}$ and $C_2{O}_4^{2-}$ is 5 : 2

So, molar ratio in balanced reaction is 2 : 5

Hence the balanced equation is

$2Mn{O}_4^{-}+5C_2{O}_4^{2-}+16H^{+}\to 2M{n}^{2+}10C{O}_2+8H_{2}O$