Question

For the redox reaction

$MnO_{4}^{-}+C_{2}O_{4}^{2 -}+H^{+} \rightarrow Mn^{2 +}+CO_{2}+H_{2}O$

The correct coefficients of the reactants for the balanced equation are

$MnO_{4}^{-}$ $C_{2}O_{4}^{2 -}$ $H^{+}$

$MnO^{-}_{4}$	$C_{2}O^{2-}_{4}$	$H^{+}$
2	16	5
2	5	16
16	5	2
5	16	2

• A. A
• B. B
• C. C
• D. D

Answer 1

Answer: (B)

n-factor of $MnO_{4}^{-}\Rightarrow 5$

n-factor of $C_{2}O_{4}^{2 -}\Rightarrow 2$

Ratio of n-factors of $MnO_{4}^{-}$ and $C_{2}O_{4}^{2 -}$ is 5 : 2

So, molar ratio in balanced reaction is 2 : 5

Hence the balanced equation is

$2MnO_{4}^{-}+5C_{2}O_{4}^{2 -}+16H^{+} \rightarrow 2Mn^{2 +}10CO_{2}+8H_{2}O$