For the reaction, ZnCO 3(s) leftharpoons ZnO (s)+ CO 2(g) expression for the partial pressure constant for the above reaction would be

Question

For the reaction, ZnCO 3(s) leftharpoons ZnO (s)+ CO 2(g) expression for the partial pressure constant for the above reaction would be (A) Kp=([ ZnO ][ CO 2]/[ ZnCO 3]) (B) Kp=(p( Zn 0) × p CO 2/P ZnCO 3) (C) Kp=p( ZnO )2 × p CO 2 (D) Kp=p CO 2

Tardigrade Admin · Accepted Answer

ZnCO 3(s) leftharpoons ZnO (s)+ CO 2(g) For solids, concentration or partial pressure is taken as unity. ∴ Kp=p CO 2

Q. For the reaction, $Z n C O_{3 (s)} ⇌ Z n O_{(s)} + C O_{2 (g)}$ expression for the partial pressure constant for the above reaction would be

$K_{p} = \frac{[ Z n O ] [ C O _{2} ]}{[ Z n C O _{3} ]}$

$K_{p} = \frac{p _{(Z n 0)} \times p _{C O_{2}}}{P _{Z n C O_{3}}}$

$K_{p} = p_{(Z n O)}^{2} \times p_{C O_{2}}$

$K_{p} = p_{C O_{2}}$

$Z n C O_{3 (s)} ⇌ Z n O_{(s)} + C O_{2 (g)}$

For solids, concentration or partial pressure is taken as unity.

$∴ K_{p} = p_{C O_{2}}$

Q. For the reaction, ZnCO3(s)​⇌ZnO(s)​+CO2(g)​ expression for the partial pressure constant for the above reaction would be

Kp​=[ZnCO3​][ZnO][CO2​]​

Kp​=PZnCO3​​p(Zn0)​×pCO2​​​

Kp​=p(ZnO)2​×pCO2​​

Kp​=pCO2​​