Question

For the reaction, $ZnCO _{3(s)} \rightleftharpoons ZnO _{(s)}+ CO _{2(g)}$ expression for the partial pressure constant for the above reaction would be

• A. $K_{p}=\frac{[ ZnO ]\left[ CO _{2}\right]}{\left[ ZnCO _{3}\right]}$
• B. $K_{p}=\frac{p_{( Zn 0)} \times p_{ CO _{2}}}{P_{ ZnCO _{3}}}$
• C. $K_{p}=p_{( ZnO )}^{2} \times p_{ CO _{2}}$
• D. $K_{p}=p_{ CO _{2}}$

Answer 1

Answer: (D)

$ ZnCO _{3(s)} \rightleftharpoons ZnO _{(s)}+ CO _{2(g)}$

For solids, concentration or partial pressure is taken as unity.

$\therefore \quad K_{p}=p_{ CO _{2}}$