Question

For the reaction, $N{H}_3+OC{l}^{-}\to N_2{H}_4+C{l}^{-}$ occurring in basic medium, the coefficient of $N_2{H}_4$ in the balanced equation will be

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (A)

The two half-reactions for the given reaction are
$2N{H}_3\to N_2{H}_4+2H^{+}+2e^{-}$
$OC{l}^{-}+2H^{+}+2e^{-}\to C{l}^{-}+H_{2}O$
On adding both the reactions, we get
$2N{H}_3+OC{l}^{-}\to N_2{H}_4+C{l}^{-}+H_{2}O$
The obtained equation is a balanced equation and in it, the coefficient of $N_2{H}_4$ is 1.