Question

For the reaction, $ N{{H}_{3}}+OC{{l}^{-}}\xrightarrow{{}}{{N}_{2}}{{H}_{4}}+C{{l}^{-}} $ occurring in basic medium, the coefficient of $ {{N}_{2}}{{H}_{4}} $ in the balanced equation will be

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (A)

The two half-reactions for the given reaction are
$ 2N{{H}_{3}}\xrightarrow[{}]{{}}{{N}_{2}}{{H}_{4}}+2{{H}^{+}}+2{{e}^{-}} $
$ OC{{l}^{-}}+2{{H}^{+}}+2{{e}^{-}}\xrightarrow[{}]{{}}C{{l}^{-}}+{{H}_{2}}O $
On adding both the reactions, we get
$ 2N{{H}_{3}}+OC{{l}^{-}}\xrightarrow[{}]{{}}{{N}_{2}}{{H}_{4}}+C{{l}^{-}}+{{H}_{2}}O $
The obtained equation is a balanced equation and in it, the coefficient of $ {{N}_{2}}{{H}_{4}} $ is 1.