Question

For the reaction $N_2{O}_4\rightleftharpoons 2N{O}_{2\left(g\right)}$ , the degree of dissociation of $N_2{O}_4$ is $0.2$ at $1atm.$ Then the $K_p$ of $2N{O}_2\rightleftharpoons N_2{O}_4$ is

Answer 1

Answer: 6

${\text{K}}_{\text{p}}=\frac{{\left[{\text{P}}_{{\text{NO}}_{\text{2}}}\right]}^2}{{\text{P}}_{{\text{N}}_2{\text{O}}_{\text{4}}}}$

${\text{ K}}_{\text{p}}=\frac{\text{4}{\alpha }^2}{1-{\alpha }^2}\text{p}$

$\Rightarrow {\mathrm{K}}_{\mathrm{p}}=\frac{4\times (0.2{)}^2}{1-(0.2{)}^2}=\frac{0.16}{0.96}$

$\text{ for}2{\text{NO}}_2\rightleftharpoons {\text{N}}_{\text{2}}{\text{O}}_4;{\text{K}}_{\text{p}}=\frac{0.96}{0.16}=6$