For the reaction H2(g)+CO2(g)CO(g)+H2O(g) If the initial concentration of [H2]=[CO2] and x mol/L of hydrogen is consumed at equilibrium, the correct expression of Kp is

Question

For the reaction H2(g)+CO2(g)CO(g)+H2O(g) If the initial concentration of [H2]=[CO2] and x mol/L of hydrogen is consumed at equilibrium, the correct expression of Kp is (A)  (x2/(1-x)2)  (B)  (x2/(2+x)2)  (C)  (x2/1-x3)  (D)  ((1+x)2/(1-x)2)

Tardigrade Admin · Accepted Answer

H2(g)+CO2(g)CO(g)+H2O(g) Initial conc. 1 1 0 0 at. equi. conc. (1-x) (1-x) x x kp=(pCO× pH2O/pH2.pCO2) =(x.x/(1-x)(1-x)) =(x2/(1-x)2)

Q. For the reaction
$H_{2} (g) + C O_{2} (g) CO (g) + H_{2} O (g)$
If the initial concentration of $[H_{2}] = [C O_{2}]$ and $x$ mol/L of hydrogen is consumed at equilibrium, the correct expression of $K_{p}$ is

$\frac{x ^{2}}{( 1 - x ) ^{2}}$

$\frac{x ^{2}}{( 2 + x ) ^{2}}$

$\frac{x ^{2}}{1 - x ^{3}}$

$\frac{( 1 + x ) ^{2}}{( 1 - x ) ^{2}}$

$H_{2} (g) + C O_{2} (g) CO (g) + H_{2} O (g)$
Initial conc. 1 1 0 0 at. equi. conc.
$(1 - x)$ $(1 - x)$ $x$ $x$
$k_{p} = \frac{p _{CO} \times p _{H_{2} O}}{p _{H_{2}} . p _{C O_{2}}}$
$= \frac{x . x}{( 1 - x ) ( 1 - x )}$
$= \frac{x ^{2}}{( 1 - x ) ^{2}}$

Q. For the reaction H2​(g)+CO2​(g)CO(g)+H2​O(g) If the initial concentration of [H2​]=[CO2​] and x mol/L of hydrogen is consumed at equilibrium, the correct expression of Kp​ is

(1−x)2x2​

(2+x)2x2​

1−x3x2​

(1−x)2(1+x)2​