Question

For the reaction
$ {{H}_{2}}(g)+C{{O}_{2}}(g)CO(g)+{{H}_{2}}O(g) $
If the initial concentration of $ [{{H}_{2}}]=[C{{O}_{2}}] $ and $ x $ mol/L of hydrogen is consumed at equilibrium, the correct expression of $ {{K}_{p}} $ is

• A. $ \frac{{{x}^{2}}}{{{(1-x)}^{2}}} $
• B. $ \frac{{{x}^{2}}}{{{(2+x)}^{2}}} $
• C. $ \frac{{{x}^{2}}}{1-{{x}^{3}}} $
• D. $ \frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}} $

Answer 1

Answer: (A)

$ {{H}_{2}}(g)+C{{O}_{2}}(g)CO(g)+{{H}_{2}}O(g) $
Initial conc. 1 1 0 0 at. equi. conc.
$ (1-x) $ $ (1-x) $ $ x $ $ x $
$ {{k}_{p}}=\frac{{{p}_{CO}}\times {{p}_{{{H}_{2}}O}}}{{{p}_{{{H}_{2}}}}.{{p}_{C{{O}_{2}}}}} $
$ =\frac{x.x}{(1-x)(1-x)} $
$ =\frac{{{x}^{2}}}{{{(1-x)}^{2}}} $