For the oxidation of glucose, Δr H°=-2808 kJ / mol and Δ r G°=-3000 kJ / mol 25 % of the energy is oxidized for muscle work. Therefore, in order to climb a hill of height 500 meters, how many gram of glucose is required for a man of mass 100 kg ? g=10 m / s 2

Question

For the oxidation of glucose, Δr H°=-2808 kJ / mol and Δ r G°=-3000 kJ / mol 25 % of the energy is oxidized for muscle work. Therefore, in order to climb a hill of height 500 meters, how many gram of glucose is required for a man of mass 100 kg ? g=10 m / s 2 (A) 100 g (B) 180 g (C) 200 g (D) 120 g

Tardigrade Admin · Accepted Answer

PE required =m g h=100 × 10 × 500=5 × 105 J Let W g be the amount of glucose required ∴ (W/180) × 3000 × (103/4)=5 × 105 or (W/180) × (3/4) × 106=5 × 105 or W=(2/3) × 180=120 g

Q. For the oxidation of glucose, Δr​H∘=−2808kJ/mol and Δr​G∘=−3000kJ/mol 25% of the energy is oxidized for muscle work. Therefore, in order to climb a hill of height 500 meters, how many gram of glucose is required for a man of mass 100kg ? g=10m/s2

100 g

180 g

200 g

120 g

PE required =mgh=100×10×500=5×105J Let Wg be the amount of glucose required ∴180W​×3000×4103​=5×105 or 180W​×43​×106=5×105 or W=32​×180=120g