1. Tardigrade
  2. Question
  3. Chemistry
  4. For the oxidation of glucose, Δr H°=-2808 kJ / mol and Δ r G°=-3000 kJ / mol 25 % of the energy is oxidized for muscle work. Therefore, in order to climb a hill of height 500 meters, how many gram of glucose is required for a man of mass 100 kg ? g=10 m / s 2

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Q. For the oxidation of glucose, $\Delta_{r} H^{\circ}=-2808\, kJ /\, mol$ and $\Delta_{ r } G^{\circ}=-3000\, kJ /\, mol$
$25 \%$ of the energy is oxidized for muscle work. Therefore, in order to climb a hill of height $500$ meters, how many gram of glucose is required for a man of mass $100\, kg$ ?
$g=10 \,m / s ^{2}$

Thermodynamics

Solution:

PE required $=m g h=100 \times 10 \times 500=5 \times 10^{5} \,J$

Let $W g$ be the amount of glucose required

$\therefore \frac{W}{180} \times 3000 \times \frac{10^{3}}{4}=5 \times 10^{5}$

or $ \frac{W}{180} \times \frac{3}{4} \times 10^{6}=5 \times 10^{5}$

or $ W=\frac{2}{3} \times 180=120\, g$